The angular speed of the merry-go-round is
Ļ = 0.10 rad/s
The angular moment of inertia of a mass, m, atĀ a radius, r, from the center of the wheelĀ is
I = mrĀ²
Therefore, the angular moment of inertia for the children are
Iā = (25 kg)*(1.0 m)Ā² = 25 kg-mĀ²
Iā = (25 kg)*(1.5 m)Ā² = 56.25 kg-mĀ²
The combined angular momentum is
Ļ(Iā + Iā) = (0.10 rad/s)*(25 + 56.25 kg-mĀ²)
Ā Ā Ā Ā Ā Ā Ā Ā = 8.125 (kg-mĀ²)/s
Answer: 8.125 (kg-mĀ²)/s
