Answer:
[tex]13.76kJ[/tex]
Explanation:
Use [tex]q=mC_s\Delta t[/tex] for those types of questions.
- [tex]m = 70g[/tex]
- [tex]C_s = 4.184 J/(g \times C^o)[/tex]
- [tex]\Delta t = 68-21 = 47[/tex]
Therefore, your formula will be like this:
[tex]70 \times 4.184 \times 47 = 13765J[/tex]
Which can also be expressed as: [tex]13.76kJ[/tex]
