Add 8x to both sides
[tex]\begin{gathered} 15-8x+8x>3-2x+8x \\ 15>3+6x \end{gathered}[/tex]Subtract 3 from both sides
[tex]\begin{gathered} 15-3>3-3+6x \\ 12>6x \end{gathered}[/tex]Divide both sides by 6
[tex]\begin{gathered} \frac{12}{6}>\frac{6x}{6} \\ 2>x \\ x<2 \end{gathered}[/tex]Interval notation solution: x < 2
