(3x - 2)(x + 6)
3x² +16x-12
a = 3, b = 16, c = - 12
a(c) = 3(-12) = -36
The factors of -36 whose sum will give +16 are -2 and 18
3x² + 18x - 2x - 12
3x(x + 6) -2(x + 6)
The factorisation: (3x - 2)(x + 6)
