Answer:
3log2+log3+logx
Step-by-step explanation:
log8(3x) can be written as log(8•3x)
Log laws says that log(ab)=log(a)+log(b)
So log (8•3•x)=log8+log3+logx
log8 can be written into prime factorization of log(2^3) and by more log laws that can be written as 3log2
