The value of y when x = 12 given the direct variation of y = 27 when x = 4 is 81
Given:
y = 27
x = 4
y = k × x
where,
k = constant of proportionality
y = k × x
27 = k × 4
27 = 4k
k = 27/4
k = 6.75
Find y when x = 12
y = k × x
y = 6.75 × 12
y = 81
Therefore, the value of y when x = 12 is 81
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