Answer:
[tex]40\ cm^3[/tex]
Step-by-step explanation:
Let the actual volume is V.
The measured volume of an object is 46 cubic cm which was 15% high from the actual volume.
According to the given condition,
[tex]V+\dfrac{15V}{100}=46\\\\\dfrac{115V}{100}=46\\\\V=\dfrac{4600}{115}\\\\V=40\ cm^3[/tex]
So, the actual volume was [tex]40\ cm^3[/tex].
