Answer:
1.6875m/s²
Explanation:
[tex] acceleration = \frac{final \: velocity \: - \: initial \: velocity}{time \: taken} [/tex]
a = unknown.
v (final velocity) = 27m/s
u (initial velocity) = 0m/s (as the car was stationary in the traffic lights).
t (time taken) = 18s
[tex]a = \frac{27 - 0}{16} [/tex]
acceleration = 1.6875m/s²
hope it helps. :)
