gabriel13Ola gabriel13Ola

01-02-2021
Mathematics

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Express X^2-8x+5 in the for (x-a)^2-b where a and b are integers

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01-02-2021

Answer:

[tex]x {}^{2} - 8x + 5 \\ = x {}^{2} - 8 x+ 5 + 11 - 11 \\ = x {}^{2} - 8x +16 - 11 \\ = (x - 4) {}^{2} - 11 \\ [/tex]

A is 4 and b is 11

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