Respuesta :

lucasella

Answer:

[tex](\frac{{3ab^{3}}}{c^{1}} )^{3}[/tex]

Step-by-step explanation:

[tex](3ab^{3} c^{-1} )^{3} =(\frac{{3ab^{3}}}{c^{1}} )^{3}[/tex]
maybe it is 27b^9a^3 over c^3