Answer:
answer B is correct
Step-by-step explanation:
Hello,
this is not allowed to divide by 0 so we need to find the zeros of
[tex]x^2+2x-15=0[/tex]
[tex]<=> x^2-3x+5x-15=0\\<=> x(x-3)+5(x-3)=0\\<=> (x+5)(x-3)=0\\<==> x=-5 \ \ or \ \ x=3[/tex]
we need x different from -5 and from 3
answer B is correct
hope this helps
