Answer:
n1=1,n2=4
Step-by-step explanation:
first divide both sides by 6 of the equation
=n^2-3n=4
n^2-3n-4=0..move the constant to the outerside
n^2-3n-4=0...write -3 as a difference
n^2+n-4n-4=0
factor out n
n×(n+1)-(4n-4)=0
nx(n+1)-4(n+1)=0
(n+1)×(n-4)=0
=n(+1=0)work out
n-4=0
n=-1
n-4=0
now solve for n
and the answer will be ;n1=-1,n2=4
