[tex]\dfrac{x+2}{14x} + \dfrac{7x}{4x}[/tex]
Common denominator of 28x
[tex]= \dfrac{2(x+2)+7(7x)}{28x} = \dfrac{51x + 4}{28x}[/tex]
We could stop there but let's continue. Next step would be:
[tex]=\dfrac{1}{7x} + \dfrac{51}{28}[/tex]
Answer: 1/(7x) + 51/28
