[tex](x - 4)(x - 2) = 24 \\ {x}^{2} - 6x + 8 = 24 \\ {x}^{2} - 6x - 16 = 0[/tex]
Use the quadratic formula
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - ( - 6) + - \sqrt{ {( - 6)}^{2} -4 \times 1 \times ( - 16)} }{2 \times 1} \\ x = \frac{6 + - 10}{2} \\ x =8 or - 2[/tex]
