Answer:
[tex]y=-\dfrac{3}{4}x+11[/tex]
Step-by-step explanation:
The equation of the line that passes through the point [tex](x_1,y_1)[/tex] and has the slope of [tex]m[/tex] is
[tex]y-y_1=m(x-x_1)[/tex]
In your case, a line passes through the point (8,5) and has a slope of [tex]-\frac{3}{4}[/tex], so its equation is
[tex]y-5=-\dfrac{3}{4}(x-8)\\ \\y-5=-\dfrac{3}{4}x+6\\ \\y=-\dfrac{3}{4}x+11[/tex]
