Respuesta :

sqdancefan

Answer:

  8.170

Step-by-step explanation:

[tex]\log_2{288}=\log_2{2^53^2}=\log_2{2^5}+\log_2{3^2}\\\\=5\log_2{2}+2\log_2{3}\approx 5+2(1.5850)=8.170[/tex]

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