m^5-m^7. probably easier for most but having a brain fart

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03-03-2019
Mathematics

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m^5-m^7. probably easier for most but having a brain fart

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jdoe0001 jdoe0001 · Answer 1 · 2019-03-03T23:31:51+01:00

jdoe0001 jdoe0001

03-03-2019

[tex]\bf m^5-m^7\implies \begin{array}{llll} m^5&(1-m^2)\\\\ &(1^2-m^2)\\\\ &(1-m)(1+m) \end{array} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill m^5(1-m)(1+m)~\hfill[/tex]

recall that

1² = 1

1⁴ = 1

1⁸⁹⁹⁹⁹⁹⁹⁹⁹ = 1

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m^5-m^7. probably easier for most but having a brain fart​

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m^5-m^7. probably easier for most but having a brain fart