Respuesta :

[tex]\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=side\\[-0.5em] \hrulefill\\ s=\frac{1}{4} \end{cases}\implies A=\left( \cfrac{1}{4} \right)^2\implies A=\cfrac{1^2}{4^2}\implies A=\cfrac{1}{16}~in^2[/tex]

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