[tex]\frac{4(3h-6)}{1+h}[/tex] ; h = -2
Since h = -2, you can substitute/plug in -2 for "h" in the expression:
[tex]\frac{4(3h-6)}{1+h}[/tex]
[tex]\frac{4(3(-2)-6)}{1+(-2)}[/tex]
[tex]\frac{4(-6-6)}{1-2}[/tex]
[tex]\frac{4(-12)}{-1}[/tex]
[tex]\frac{-48}{-1}[/tex]
48
