[tex]3ax-\frac{n}{5}=-4\ \ \ |Add\ \frac{n}{5}\ to\ both\ sides\\\\
3ax=-4+\frac{n}{5}\\\\
3ax=-\frac{20}{5}+\frac{n}{5}\\\\
3ax=\frac{-20+n}{5}\ \ \ |Divide\ by\ 3a\\\\
x=\frac{-20+n}{5}*\frac{1}{3a}\\\\
x=\frac{-20+n}{15a}\\\\Asnwer\ is\ x=\frac{-20+n}{15a}.[/tex]
