[tex]x = 4z[/tex]
[tex]2y = 4z[/tex]
Dividing both sides by two,
[tex]y = 2z[/tex]
OK, part 1.
[tex]x+4y+z = 4z + 4(2z) +z = 13z[/tex]
When [tex]z=2[/tex] then [tex]x+4y+z =13(2)=26[/tex]
Part 2.
[tex]2x+3y+2z= 2(4z) +3(2z) + 2z = 16z[/tex]
When [tex]z=2[/tex] then [tex]2x+3y+2z=16(2)=32[/tex]
